Volume2020-12-31T18:59:07+10:00

Timetable Forums Standard Measurement Volume

Viewing 5 posts - 1 through 5 (of 5 total)
  • Author
    Posts
  • Admin
    Keymaster
    Post count: 1622
    Cube

    vol_cube

    $$V=s^3$$

     

    Rectangular Prism

    vol_rectangularprism

    $$V=LWH$$

     

    Triangular Prism

    vol_triangularprism

    $$V=\frac{1}{2}bhL$$

     

    Pyramid

    vol_pyramid

    $$V=\frac{1}{3}LWH$$

     

    Cylinder

    vol_cylinder

    $$V=\pi r^2h$$

     

    Cone

    vol_cone

    $$V=\frac{1}{3}\pi r^2h$$

     

    Sphere

    vol_sphere

    $$V=\frac{4}{3}\pi r^3$$

    Truncated Cone

    j_cone_0001

    $$V=\frac13\pi R^2\,H-\frac13\pi r^2\,h $$

    or

    $$V=\frac13\pi(R^2\,H- r^2\,h)$$

     

     

     

     

     

    Admin
    Keymaster
    Post count: 1622

    vol_chalThe diagram shows a cone inscribed in a hemisphere. What is the ratio of the volume of the cone to the volume of the hemisphere?
    a. 1:3
    b. 2:3
    c. 1:2
    d. More information needed

    Volume of hemisphere = $$\frac12\times\frac43\times\pi\times r^3$$

    $$=\frac23\pi r^3$$

    Volume of cone = $$\frac13\times\pi\times r^2\times h$$
    since h = r

    V =$$\frac13\times\pi\times r^2\times r$$

    $$=\frac13\pi r^3$$

    Ratio of volume of Cone to volume of Hemisphere

    $$\frac13\pi r^3:\frac23\pi r^3$$

    $$\frac13:\frac23$$ × both sides by 3

    C 1:2

    Admin
    Keymaster
    Post count: 1622

    A cylinder has a radius of 10cm and a height of 15 cm.

    Find the volume.

    ##V=\pi\times10^2\times20##

    = 6283.19 cm2

    V = $$\pi r^2h$$

    r = 10, h = 20

    Admin
    Keymaster
    Post count: 1622

    A Christmas tree decoration in the shape of a sphere is 4.5cm in diameter.
    a. Find the volume of the decoration. V =43πr3.
    b. The 12 decorations are to fit into a rectangular box which is 10cm wide and 5cm high. What is the minimum length that the box can be if it is to hold all 12 decorations?

    a. V = 4/× π × 2.253

    = 47.7cm3

    Use the volume formula for a sphere: $$V=\frac{4}{3}\pi r^3$$ and calculate, where r = ½ of the diameter 
    radius = ½ × 4.5 = 2.25
    b. 2 × 1 = 2  If it is 10cm wide, that means it can fit 2 balls across its width.

    2 × 1 × 6 = 12 balls If 5cm high, can only fit one ball.  so if we can fit two per row, and we need 12, so it has to be able to fit six rows along its length, 2 × 1 × 6 = 12 balls
    6 × 4.5 = 27cm now if each ball is 4.5cm in diameter, then 6 balls long to fit the 12, so 6 × 4.5 
    Admin
    Keymaster
    Post count: 1622
    A sphere has a volume of 180m3, find the radius.

    V = $$\frac43\pi r^3$$

    = 180

    ##r^3= 180\div\pi \div \frac43##

    divide both sides by $$\frac43$$ then $$\pi$$
    r3 = 42.97
    r = 3.5 m
    cube root both sides to find r
Viewing 5 posts - 1 through 5 (of 5 total)
  • You must be logged in to reply to this topic.
Go to Top