Stopping Distance, Distance, Speed and Time2021-01-01T13:19:27+10:00

Timetable Forums Standard Formulae & Equations Stopping Distance, Distance, Speed and Time

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    Distance, Speed and Time

    $$d=st$$

    $$s=\frac{d}{t}$$

    $$t=\frac{d}{s}$$

    Stopping Distance

    Stopping Distance = Braking distance + Reaction time distance

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    Sarah is travelling at 75 km/h and suddenly has to stop. Her reaction time is 4.2 seconds. She comes to a stop 116.19 m further down the road. Use the braking distance formula d = kv2 to find how much further, to the nearest metre, her stopping distance would be if she was travelling 12 km/h faster.

    Stopping distance = braking distance + reaction time distance

    Find the reaction time distance

    75 km/h change to m/s by multiplying  by 1000 to change km to m and dividing by 60 and then divide by 60 again to change from hours to minutes to seconds

    speed in m/s = 75 × 1000 ÷ 60 ÷ 60

    = 20.83 m/s

    reaction time = 4.2 s
    reaction time distance = 20.83 × 4.2

    = 87.5m

    116.19 = braking distance + 87.5

    braking distance = 116.19 -87.5

    = 28.69 m

    substitute this distance into the formula to find k

    28.69 =  × 752

    $$k=\frac{28.69}{5625}$$

    k = 0.0051

    ∴ = 0.0051v2

     

    12 km/h faster = 75 + 12

    = 87

    find braking distance

    d = 0.0051 × 872

    d = 38.6m

    find reaction distance

    speed in m/s = 87 × 1000 ÷ 60 ÷ 60

    = 24.16 m/s

    reaction time distance = 24.16 × 4.2

    = 101.5 m

    stopping distance = 38.6 + 101.5

    = 140.1 m

    difference is 140.1 – 116.19

    = 23.91 m

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    Raine is driving at a speed of 80 km/h. It takes Raine two seconds to react to a dangerous situation before applying the brakes. The stopping distance (in m) is given by the formula: Stopping distance: $$d=\frac{5Vt}{18}+\frac{V^2}{170}$$. How far will Raine travel in her car after applying the brakes using this formula?

    Substitute V = 80 and t = 2
    $$d=\frac{5\times80\times2}{18}+\frac{80^2}{170}$$
    = 82.0915
    = 82 m

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    The stopping distance (d) of a scooter travelling with a speed s metres per second is given by the formula d = ¼(s2 + s + 2). What is the stopping distance given a speed of  8 metres per second?

    substitute s = 8 into the formula

    s = ¼ × (82 + 8 + 2)

    s = 18.5 m

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    Maryam is driving 80 km/h when she sees a cyclist fall from his bike. Her reaction time is 1.8 seconds and her braking distance is 35 metres. What is her stopping distance?
    80 × 1000 ÷ 60 ÷ 60 Step 1: Change 80 km/h into m/s
    = 22.2 m multiply by 1000 to go from km to m and then divide by 60 to go from hours to minutes and divide by 60 again to get to seconds
    reaction distance = 22.2 × 1.8
    = 40 m
    Step 2: her reaction time is 1.8 seconds, so her reaction distance is 1.8 lots 22.2
    40 m + 35 m Step 3: find her total stopping distance = reaction time + braking distance
    = 75 m  
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